Answer
$y=0.241\cdot x^{2.343}$
Work Step by Step
Let $y=ax^b$.
Then our equations are: $6.2=a4^b$ and $23=a7^b$.
If we divide the second equation by the first one we get:
$1.75^b=(\frac{23}{6.2})\\b=\ln_{1.75}\frac{23}{6.2}\approx2.343$.
Then $23=a7^{2.343}\\a=\frac{23}{7^{2.343}}\approx0.241$.
Thus $y=0.241\cdot x^{2.343}$