Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Mixed Review - Page 522: 65

Answer

See below

Work Step by Step

Given: $f(x)=x^3-2x^2+5$ We can see that there are 2 sign changes. There might be 2 or 0 positive zeros. $f(-x)=(-x)^3-2(-x)^2+5=-x^3+2x^2+5$ There is one sign change here. Thus, there is one zero. The possible combinations: 2 positive real, 1 negative real 0 positive real, 1 negative real, 2 imaginary.
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