Answer
5
Work Step by Step
Simplifying using the rules of radicals, we find:
$$\left(\sqrt[3]{2x-7}\right)^3=\left(\sqrt[3]{8-x}\right)^3 \\ 2x-7=8-x \\ x=5$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.5 Apply Properties of Logarithms - 7.5 Exercises - Mixed Review - Page 513: 81
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