Answer
6.4 magnitude
Work Step by Step
Given: $M=0.29(\ln E)-9.9$
Substituting $E=2.5 \times10^{24}$ we have:
$$M=0.29(\ln (2.5 \times10^{24}))-9.9\\=0.29(56.1783)-9.9\\=6.3917\approx6.4$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.4 Evaluate Logarithms and Graph Logarithmic Functions - 7.4 Exercises - Problem Solving - Page 505: 61a
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