Answer
$$x=2,\:x=1$$
Work Step by Step
Using the rules of Algebra, we find:
$$\left(\sqrt{15x+34}\right)^2=\left(x+6\right)^2\\ 15x+34=x^2+12x+36 \\ x^2-3x+2=0 \\ x=2,\:x=1$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.3 Use Functions Involving e - 7.3 Exercises - Mixed Review - Page 498: 68
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