Answer
$\approx98.01$
Work Step by Step
Plugging in $I=325, t=3.5$ into the given function we get: $A=325(0.71)^{3.5}\approx98.01$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.2 Graph Exponential Decay Functions - 7.2 Exercises - Problem Solving - Page 490: 30b
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
