Answer
$800(1+\frac{0.02}{365})^{365\cdot t}$
Work Step by Step
The amount can be obtained by the formula $A=P(1+\frac{r}{n})^{nt}$ where $P$ is the initial amount, $r$ is the annual interest rate which is compounded $n$ times per year over $t$ years.
Hence here: $A(t)=P(1+\frac{r}{n})^{nt}=800(1+\frac{0.02}{365})^{365\cdot t}$
