Answer
$\approx2660.8$
Work Step by Step
The amount can be obtained by the formula $A=P(1+\frac{r}{n})^{nt}$ where $P$ is the initial amount and $r$ is the annual interest rate which is compounded $n$ times per year over $t$ years.
Hence here: $A=P(1+\frac{r}{n})^{nt}=P(1+\frac{0.04}{365})^{365\cdot3}=3000\\P=\frac{3000}{(1+\frac{0.04}{365})^{365\cdot3}}\approx2660.8$
