Answer
See below
Work Step by Step
Given: $\sqrt[4] 16x^3y^4z=2x^ayz^b\\16x^3y^4z=16x^{4a}y^4z^{4b}\\x^3z=x^{4a}z^{4b}$
The exponents are equal on both sides:
$4a=3\\4b=1$
Then $a=\frac{3}{4}\\b=\frac{1}{4}$
Hence, $a+b=1$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 6 Rational Exponents and Radical Functions - Standardized Test Practice - Gridded Response - Page 473: 11
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