Answer
-8
Work Step by Step
We know the following rule: $$(\sqrt[n] x)=x^{\frac{1}{n}}$$
Using this as well as the rules of exponents learned in a past chapter (and listed on page 330, if review is necessary), we find:
$$ -\frac{1}{\left(\sqrt[5]{32}\right)^{-3}} \\ -\frac{1}{\left(\sqrt[5]{32}\right)^{-3}} \\ -8$$