Chapter 6 Rational Exponents and Radical Functions - 6.4 Use Inverse Functions - 6.4 Exercises - Skill Practice - Page 443: 41

$$y=\sqrt[6]{\frac{-5x+40}{2}},\:y=-\sqrt[6]{\frac{-5x+40}{2}}$$

Switching the elements of the domain and the range (in other words, the dependent and independent variables), we find that the inverse is: $$x=-\frac{2}{5}y^6+8 \\ y=\sqrt[6]{\frac{-5x+40}{2}},\:y=-\sqrt[6]{\frac{-5x+40}{2}}$$