Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - 6.4 Use Inverse Functions - 6.4 Exercises - Problem Solving - Page 445: 51a

Answer

Use symmetry about the line $y=x$

Work Step by Step

We are given the function: $$g(x)=-x.$$ Graph the function $g$. Let $(x,y)$ be a point on the graph of $g$. Because $g(x)=-x$, the coordinates can be written as $(x,-x)$. The symmetric of this point with respect to the line $y=x$ belongs to the graph of $g^{-1}$. But this symmetric is $(-x,x)$ which belongs to the graph of $g$. Therefore the two graph are identical, so $g(x)=g^{-1}(x)$. Find the inverse $g^{-1}$ of the function $g$ algebraically: $$\begin{align*} g(x)&=-x\quad&&\text{Write original function.}\\ y&=-x\quad&&\text{Replace }g^{-1}(x)\text{ by }y\\ x&=-y\quad&&\text{Switch }x\text{ and }y.\\ -x&=y\quad&&\text{Divide each side by }-1. \end{align*}$$ The inverse function of $g$ is $g^{-1}(x)=-x$.
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