Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - 6.4 Use Inverse Functions - 6.4 Exercises - Problem Solving - Page 444: 48a

Answer

See below

Work Step by Step

Given: $C=\frac{5}{9}(F-32)\\F-32=\frac{9}{5}C\\F=\frac{9}{5}C+32$
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