Answer
$f(x)=\frac{4}{x}$ and $g(x)=3x^2+7$
Work Step by Step
Let $f(x)=\frac{4}{x}$ and $g(x)=3x^2+7$. Then $h(x)=f(g(x))=f(3x^2+7)=\frac{4}{3x^2+7}$
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