Answer
See below.
Work Step by Step
$h(g(x))=h(2x-7)=\frac{2x-7+4}{3}=\frac{2x-3}{3}$
The denominator of this function's first term cannot be $0$, thus $x\ne0$. Thus the domain is all real numbers apart from $x=0$.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 6 Rational Exponents and Radical Functions - 6.3 Perform Function Operations and Composition - 6.3 Exercises - Skill Practice - Page 432: 32
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
