Answer
See below
Work Step by Step
$d=1.9[(5.5\times10^{-4})l]^{1/2}$
Substitute:
$d=1.9[(5.5\times10^{-4})100]^{1/2}\\=1.9(\frac{5.5}{100})^{1/2}\\=0.19(5.5)^{1/2}\\\approx0.446$
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