Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - Standardized Test Practice - Extended Response - Page 411: 21b

Answer

$1067471$

Work Step by Step

From part a, we have: $HB=-0.38742t^4+57.9324t^3-1347.23t^2-12735.4t+1385720$ For 1995, $t=15$ Substitute: $HB=-0.38742(15)^4+57.9324(15)^3-1347.23(15)^2-12735.4(15)+1385720\approx1067471$
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