Answer
2704 $in^2$
Work Step by Step
We found: $T(x)=8x^3+36x^2+48x+16\\C(x)=8x^3$
From part c, we have $I(x)=T(x)-C(x)\\=8x^3+36x^2+48x+16-8x^3\\=36x^2+48x+16$
Substitute $x=8$: $I(x)=36(8)^2+48(8)+16\\=2304+384+16\\=2704$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - Mixed Review of Problem Solving - Lessons 5.1-5.5 - Page 369: 2d
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