Answer
See below
Work Step by Step
Given: $f(x)=8-x^2$
Rewrite as $f(x)=-x^2+8$
The degree is $2$.
The leading coefficient is $-1$.
The constant term is $8$.
This is also a quadratic function.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - Investigating Algebra Activity - 5.2 End Behavior of Polynomial Functions - Draw Conclusions - Page 336: 3
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