Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.9 Write Polynomial Functions and Models - Guided Practice for Examples 1 and 2 - Page 394: 2

Answer

$f(x)=-2(x+1)(x-2)(x-3)$

Work Step by Step

If the function has x-intercepts $a,b,c,$ then it has the form $f(x)=k(x-a)(x-b)(x-c)$. Here the x-intercepts are $-1,2,3$, hence $f(x)=k(x+1)(x-2)(x-3)$. The function also goes through $(0,-12)$, hence: $-12=k(1)(-2)(-3)=6k\\k=-2$ Hence $f(x)=-2(x+1)(x-2)(x-3)$
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