Chapter 5 Polynomials and Polynomial Functions - 5.7 Apply the Fundamental Theorem of Algebra - 5.7 Exercises - Problem Solving - Page 386: 63

$x=0,60$

Here, we have $2.724 \times 10^{-7} x^4-3.269 \times 10^{-5} x^3+9.806 \times 10^{-4} x^2=0$ Re-arrange as: $2.724 x^4-326.9x^3+9806 x^2=0$ or, $x^2(2.724 x^2-326.9x+9806)=0$ Now, $2.724 x^2-326.9x+9806=0$ $x=\dfrac{-(-326.9)\pm \sqrt {(326.9)^2-(4)(2.724)(9806)}}{(2)(2.724)}=59.24, 60.77$ Hence, $x=0,60$