Answer
$3$ and $-3$.
Work Step by Step
Since $f(-2)=0$, $(x+2)$ is a factor of $f(x)$. Thus $f(x)=(x+2)(x^2-9)=(x+2)(x+3)(x-3)$
Thus the other zeros are $3$ and $-3$.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - 5.5 Apply the Remainder and Factor Theorems - Guided Practice for Examples 5 and 6 - Page 365: 7
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