Answer
$x^2+x-4+\frac{11}{x+3} $
Work Step by Step
Dividing the two polynomials using long division, we find:
$$\frac{x^3+4x^2-x-1}{x+3} \\ x^2+\frac{x^2-x-1}{x+3} \\ x^2+x+\frac{-4x-1}{x+3} \\ x^2+x-4+\frac{11}{x+3} $$
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