Answer
$$x^2+4x+7+\frac{9}{x-1}$$
Work Step by Step
Dividing the two polynomials using long division, we find:
$$x^2+\frac{4x^2+3x+2}{x-1} \\ x^2+4x+\frac{7x+2}{x-1} \\ x^2+4x+7+\frac{9}{x-1}$$
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