Answer
$2\pi x^3-13\pi x^2+8\pi x+48\pi$
Work Step by Step
Plugging in the values we get: $V=\pi(x-4)(x-4)(2x+3)=\pi(x^2-4x-4x+16)(2x+3)=\pi(x^2-8x+16)(2x+3)=\pi(2x^3-16x^2+32x+3x^2-24x+48)=\pi(2x^3-13x^2+8x+48)=2\pi x^3-13\pi x^2+8\pi x+48\pi$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - 5.3 Add, Subtract, and Multiply Polynomials - 5.3 Exercises - Skill Practice - Page 350: 49
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