Answer
$\frac{4r}{h}$
Work Step by Step
Using part a) and b): $\frac{V_{balls}}{V_{cans}}=\frac{4r^3\pi}{r^2\pi h}=\frac{4r^3}{r^2 h}=\frac{4r^{3-2}}{h}=\frac{4r}{h}$
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