Answer
$x=22$
Work Step by Step
Find the zeros of this function: $x^2-25x+66=0$
The equation is in the form $ax^2+bx+c$
with $a=1,b=-25,c=66$
To find $x$:
$x=\frac{-b \pm \sqrt b^2-4ac}{2a}=\frac{-(-25) \pm \sqrt (-25)^2-4.1.66}{2.1}=\frac{25 \pm \sqrt 361}{2}$
$x=\frac{25+19}{2}=22$
or $x=\frac{25-19}{2}=3$
Since $22 \gt 3 $, $22$ is the greatest zero of the function.
