Answer
$$x=\frac{4\pm\sqrt2i}{6}$$
Work Step by Step
We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain:
$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$x=\frac{8\pm \sqrt{(-8)^2-4(6)(3)}}{2(6)}$$
$$x=\frac{4\pm\sqrt2i}{6}$$
