Answer
Purely imaginary number
Work Step by Step
Recall, in the given form, $a$ is the real part of the imaginary number. Thus, if $a$ equals 0 and $b$ does not, then the number is purely imaginary.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - Chapter Review - Page 318: 2
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