Answer
$2 \lt x\lt 8 $
Work Step by Step
Given $x^2 -10x \lt-16$. Rewrite as: $x^2-10x+16 \lt 0$. Then make a table of values:
Notice that $x^2-10x+16 \lt 0$ when $2 \lt x\lt 8 $.
The solution of the inequality is $2 \lt x\lt 8 $.
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