Chapter 4 Quadratic Functions and Factoring - 4.8 Use the Quadratic Formula and the Discriminant - 4.8 Exercises - Mixed Review - Page 299: 86

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The form of the quadratic function is: $y=a(x-p)(x-q)$ where $a=-2\\p=3\\q=1$ Thus, the intercepts occur at $(3,0)$ and $(1,0)$ The x-coordinate of the vertex is: $x=\frac{p+q}{2}=\frac{1+3}{2}=2$ Find the y-coordinate: $y=-2(2-3)(2-1)=-2(-1)(1)=2$ Hence, the vertex is $(2,2)$