Answer
The equation of the line is $y=\displaystyle \frac{1}{2}x$
Work Step by Step
$(x_{1},y_{1})=(6,3)$
$(x_{2},y_{2})=(8,4)$
Find the slope of the line: $m=\displaystyle \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m=\displaystyle \frac{4-3}{8-6}=\frac{1}{2}$
You know the slope and a point on the line, so use point-slope form with either
given point to write an equation of the line. Choose $(x_{1},y_{1})=(6,3).$
$ y-y_{1}=m(x-x_{1})\qquad$ ...substitute $3$ for $y_{1},\ \displaystyle \frac{1}{2}$ for $m$ and $6$ for $x$.
$ y-3=\displaystyle \frac{1}{2}(x-6)\qquad$ ...apply the Distributive Property.
$ y-3=\displaystyle \frac{1}{2}x-3\qquad$ ...add $3$ to each side.
$y=\displaystyle \frac{1}{2}x$
