Answer
$$\ z=\pm 2i$$
Work Step by Step
For imaginary numbers, we know that standard form is $a\pm bi$, where $a$ is the real part and $b$ is the imaginary part. To get the expression into this form, we combine like terms like we did with polynomials. Doing this, we find:
$$z^2=-4 \\ z=\pm 2i$$