Answer
The solutions are $2+\sqrt{\frac{40}{3}}$ and $2-\sqrt{\frac{40}{3}}$.
Work Step by Step
$ 3(x-2)^{2}=40\qquad$ ...divide each side with $3$.
$(x-2)^{2}=\displaystyle \frac{40}{3}\qquad$ ...take square roots of each side.
$\sqrt{(x-2)^{2}}=\sqrt{\frac{40}{3}}\qquad$ ...simplify.
$ x-2=\pm\sqrt{\frac{40}{3}}\qquad$ ...add $2$ to each side.
$ x-2+2=\pm\sqrt{\frac{40}{3}}+2\qquad$ ...simplify.
$x=2\pm\sqrt{\frac{40}{3}}$
