Answer
See below.
Work Step by Step
In terms of $c$: $c=a(x+b)^2$
In terms of $a$ (if $x\ne -b$): $c=a(x+b)^2\\a=\frac{c}{(x+b)^2}$
In terms of $b$: $c=a(x+b)^2\\(x+b)^2=\frac{c}{a}\\x+b=\pm\sqrt{\frac{c}{a}}\\b=\pm\sqrt{\frac{c}{a}}-x$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.5 Solve Quadratic Equations by Finding Square Roots - 4.5 Exercises - Skill Practice - Page 270: 37
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