Answer
$\sqrt{3}\cdot\sqrt{27}=9$
Work Step by Step
$\sqrt{3}\cdot\sqrt{27}\qquad$ ...apply the Product Property $\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$
$=\sqrt{3\cdot 27}\qquad$ ...simplify.
$=\sqrt{81}\qquad$ ...take square root.($9^{2}=81$)
$=9$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.5 Solve Quadratic Equations by Finding Square Roots - 4.5 Exercises - Skill Practice - Page 269: 6
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