Answer
$2$ ft
Work Step by Step
Our equation according to the exercise: $(12+2x)(8+2x)-12\cdot8=12\cdot8\\96+16x+24x+4x^2-96=96\\4x^2+40x-96=0\\x^2+10x-24=0\\(x+12)(x-2)=0$
Thus $x=-12$ or $x=2$, but $x$ has to positive, thus $x=2$.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.4 Solve ax(squared) + bx + c = 0 by Factoring - 4.4 Exercises - Problem Solving - Page 264: 63
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