Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - Guided Practice for Example 1 - Page 252: 1

$$(x-6)(x+3)$$

Since the coefficient of the squared term is one, we know that the expression must factor to: $$ (x\pm a)(x\pm b)$$ Here, we see that a and b must multiply to get $-18$ and add to get $-3$. Thus, we find that the solution is: $$(x-6)(x+3)$$