Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Skill Practice - Page 257: 60

Answer

5

Work Step by Step

We know: $$(x+2)(x+7) = 84 \\ x^2 + 7x+2x +14 = 84 \\ x^2+9x-70=0$$ Since the coefficient of the squared term is one, we know that the expression must factor to: $$ (x\pm a)(x\pm b)$$ Here, we see that a and b must multiply to get $-70$ and add to get $9$. Thus, we find that the solution is: $$(x+14)(x-5)$$ Thus, setting each factor equal to zero, we find that the solutions are: $$ x=-14,5$$ x must be positive, so: $$x=5$$
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