Answer
$x=8$.
Work Step by Step
The equation from part b): $600+464=(20+x)(30+x)\\1064=x^2+50x+600\\x^2+50x-464=0\\(x+58)(x-8)=0$
Thus $x=8$ or $x=−58$ but $x$ has to be positive, thus $x=8$.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Problem Solving - Page 257: 67c
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