Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.2 Graph Quadratic Functions in Vertex or Intercept Form - 4.2 Exercises - Mixed Review - Page 251: 65

Answer

$\begin{bmatrix} 0& 0\\ 7 & -2 \end{bmatrix} $

Work Step by Step

Given: $A=\begin{bmatrix} -1 & 3\\ 2 & -5 \end{bmatrix}$ so $2A=\begin{bmatrix} -2 & 6\\ 4 & -10 \end{bmatrix}$ Hence, $\begin{bmatrix} -2 & 6\\ 4 & -10 \end{bmatrix}+\begin{bmatrix} 2 & -6\\ 3 & 8 \end{bmatrix}=\begin{bmatrix} 0& 0\\ 7 & -2 \end{bmatrix}$
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