Answer
See the graph
Work Step by Step
We observe that the given function is in the form $y=a(x-h)^2 + k$. The constants are $a =\frac{1}{2}, h=3, k=-4$. Because $a \lt0$, the parabola opens down.
Plot the vertex $(h, k) = (3, -4)$ and draw the axis of symmetry $x =3$.
Evaluate the function for two values of x.
$x=0 \rightarrow y=\frac{1}{2}$
$x=1 \rightarrow y=-2$
Plot the points $(0,\frac{1}{2})$ and $(1, -2)$ and their reflections in the axis of symmetry.
Draw a parabola through the plotted points.