Chapter 4 Quadratic Functions and Factoring - 4.10 Write Quadratic Functions and Models - 4.10 Exercises - Skill Practice - Page 313: 23

$y=3(x-3)(x-7)$

We already know $y$, $x$, $p$ and $q$ from the given x-intercepts and the point, so in order to get the quadratic function we need to find $a$... $y=a(x-p)(x-q)$ $-9=a(6-3)(6-7)$ $-9=-3a$ $a=\frac{9}{3}$ $a=3$ Therefore the function is... $y=3(x-3)(x-7)$