Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.10 Write Quadratic Functions and Models - 4.10 Exercises - Problem Solving - Page 314: 48c

Answer

See below

Work Step by Step

The equation from part (b), $Hours=0.85714t^2+21.77143t+33.31429$ For the year 2010, it will be $t=13$. Substitute: $0.85714(13)^2+21.77143(13)+33.31429\\ \approx 461.2$ The average number of hours a person will spend on the Internet in 2010 is $461.2$
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