Chapter 4 Quadratic Functions and Factoring - 4.1 Quadratic Functions in Standard Form - 4.1 Exercises - Skill Practice - Page 241: 43

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Since $x=4$, we obtain: $a(x-4)^2-1=0$ Letting $a=1,b=-1$, we have: $1(x-4)^2-1=0\\ \rightarrow x^2-8x+15=0$ (red line) Letting $a=2,b=-2$, we have: $2(x-4)^2-2=0\\ \rightarrow 2x^2-16x+32=0$ (blue line) Letting $a=3,b=-3$, we have: $3(x-4)^2-3=0\\ \rightarrow 3x^2-24x+45=0$ (green line)