Answer
See the graph
Work Step by Step
Given: $y=x^2-2x-1$
The coefficients are $a =1$, $b =-2$, and $c=-1$. Because $a > 0$, the parabola opens up.
Find the vertex.
$x=-\frac{b}{2a}=\frac{-(-2)}{2.1}=1$
Then find the y-coordinate of the vertex.
$y=1^2-2.1-1=-2$
Draw the axis of symmetry $x =1$
The y-intercept is $-1$. Plot the point $(0, -1)$. Then reflect this point in the axis of symmetry to plot another point, $(2,-1)$.
Evaluate the function for another value of $x$, such as $x =-1$.
$y=(-1)^2-2(-1)-1=2$
Plot the point $(-1, 2)$ and its reflection $(3, 2)$ in the axis of symmetry.
Draw a parabola through the plotted points.
