Answer
The graph is attached.
Work Step by Step
We know that parabolas follow the form $y=ax^2+bx+c$. Thus, once the parabola is in this form, we can graph it. After all, we know that $-\frac{b}{2a}$ is the vertex, and c is the y-intercept. Also, if a is positive, the graph opens up, while if a is negative, the graph opens down. Knowing this, we create the graph. Recall, if there is ever any difficulty with graphing, one can always create a table of values and plot those points to see the shape of the curve.
As the problem requests, the graph of $y=x^2$ is included for reference.
![](https://gradesaver.s3.amazonaws.com/uploads/solution/bf9d0d86-e41e-4756-8d81-8266bc01d787/steps_image/small_1561051168.jpg?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240908%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240908T001623Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=0d618bf6d77a1fdb7a212966e8ab5766dd6e1733221c694d406a642fa87bfb20)