Answer
See graph
Work Step by Step
We have to draw the graph of the following equation with $3$ variables;
$$4x+3y+2z=12.$$
Find the $x$-intercept by setting $y=0$ and $z=0$ and solving the resulting equation:
$$4x=12\Rightarrow x=3$$
The $x$-intercept is $3$, so we will plot the point $(4,0,0)$.
Find the $y$-intercept by setting $x=0$ and $z=0$ and solving the resulting equation:
$$3y=12\Rightarrow y=4$$
The $y$-intercept is $4$, so we will plot the point $(0,4,0)$.
Find the $z$-intercept by setting $x=0$ and $y=0$ and solving the resulting equation:
$$2z=12\Rightarrow z=6$$
The $z$-intercept is $6$, so we will plot the point $(0,0,6)$.
We join the $3$ points and obtain a triangular region which is a part of the graph of the given equation that lies in the first octant.
