Answer
$$\begin{pmatrix}-2&6&-15\\ 6&0&-3\end{pmatrix}$$
Work Step by Step
Finding the product of the matrices, we obtain:
$$\begin{pmatrix}\left(-2\right)\cdot \:6+5\cdot \:2&\left(-2\right)\left(-3\right)+5\cdot \:0&\left(-2\right)\cdot \:5+5\left(-1\right)\\ 0\cdot \:6+3\cdot \:2&0\cdot \left(-3\right)+3\cdot \:0&0\cdot \:5+3\left(-1\right)\end{pmatrix} \\ \begin{pmatrix}-2&6&-15\\ 6&0&-3\end{pmatrix}$$