Chapter 3 Linear Systems and Matrices - 3.3 Graph Systems of Linear Inequalities - 3.3 Exercises - Mixed Review - Page 173: 53

$x=\frac{3}{8}$ $y=-2$

Given: $8x-2y=7$ $16x+5y=-4$ Multiply both sides of the first equation with $-2$: $-16x+4y=-14$ $16x+5y=-4$ Using elimination to solve for y: $-16x+4y=-14$ $16x+5y=-4$ ______________________ $9y=-18$ $y=-2$ Solve for x: $8x-2(-2)=7$ $8x=3$ $x=\frac{3}{8}$